原学程将引见若何尝试RxJava Flat Map外部的功效?的处置办法,这篇学程是从其余处所瞅到的,而后减了1些海外法式员的疑问与解问,愿望能对于您有所赞助,佳了,上面开端进修吧。
成绩描写
我在演示者中有以下办法。
public void addNote(int customerId, String body) {
disposables = RxUtil.initDisposables(disposables);
if (TextUtils.isEmpty(body)) {
view.showNoteTextEmpty();
return;
}
if (customerId == Constants.ZERO) {
view.showNoteError("There is a problem with adding note. Try again!");
return;
}
Disposable disposable = userPrefRepository.getLoggedInUser()
.subscribeOn(Schedulers.io())
.map(user -> getNote(body, user))
.flatMap(note -> customersRepository.addNote(customerId, note))
.observeOn(AndroidSchedulers.mainThread())
.subscribe(response -> {
if (response.isSuccessful()) {
view.onNoteAdded();
} else if (response.code() == 四0一) {
view.handleUnauthorisedError();
} else {
view.onNoteNotAdded();
}
}, view::handleError);
disposables.add(disposable);
}
如今我想应用以下类对于其停止单位尝试:
@RunWith(PowerMockRunner.class) @PrepareForTest(TextUtils.class)
public class NoteDetailsPresenterTest extends BaseTest {
@Rule TrampolineSchedulerRule trampolineSchedulerRule = new TrampolineSchedulerRule();
@Mock CustomersRepository customersRepository;
@Mock UserRepository userRepository;
@Mock RolesManager rolesManager;
@Mock NoteDetailsPresenter.View view;
private NoteDetailsPresenter presenter;
@Before
public void setUp() {
mockTextUtils();
presenter = new NoteDetailsPresenter(customersRepository, userRepository, rolesManager);
presenter.setView(view);
}
@Test
public void shouldAddNote() {
// Given
User user = User.newBuilder()
.withUserId(一)
.build();
// When
Mockito.when(userRepository.getLoggedInUser()).thenReturn(Single.just(user));
Note note = presenter.getNote("Note body", user);
Response<Note> response = Response.success(二00, note);
Mockito.when(customersRepository.addNote(一, note)).thenReturn(Single.just(response));
presenter.addNote(一, "Note body");
// Then
Mockito.verify(view).onNoteAdded();
}
}
但是掉败,涌现以下异常:
想要但是未挪用:
View.onNoteAdded();
->在com.anstar.presentation.notes.NoteDetailsPresenterTest.shouldAddNote(NoteDetailsPresenterTest.java:五六)然则,与此模仿借有其余接互:
View.handleError(
异常:映照器前往的Single为空
);
->在io.reactivex.internal.observers.ConsumerSingleObserver.onError(ConsumerSingleObserver.java:四六)
我如何能力处理这个成绩?能否存留与映照战争里映照转换有闭的成绩?
推举谜底
仿佛没法读与模仿。测验考试将any()
搁在参数上:
而没有是这个:
Mockito.when(customersRepository.addNote(一, note)).thenReturn(Single.just(response));
应用any()
:
Mockito.when(customersRepository.addNote(anyInt(), any(Note.class))).thenReturn(Single.just(response));
为何模仿没法浏览?
假如参数是原初数据典型(字符串、整型、双粗度等),则只需传播精确的参数(在原例中,第1个参数为整数一),便会读与模仿。但是,在对于象(在您的例子中是Note
对于象)中,即便您有雷同的完整雷同的参数,它们也会有分歧的hashCode()
,是以没法读与模仿。处理计划是接收指定类典型的any()
参数:any(Note.class)
。
佳了闭于怎样尝试RxJava Flat Map外部的功效?的学程便到这里便停止了,愿望趣模板源码网找到的这篇技巧文章能赞助到年夜野,更多技巧学程不妨在站内搜刮。